std::stable_partition
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在头文件 <algorithm> 中定义
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template< class BidirIt, class UnaryPredicate > BidirIt stable_partition( BidirIt first, BidirIt last, UnaryPredicate p ); |
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重新排序的范围
[first, last)
在这样一种方式中的元素,所有元素的谓词p
回报true之前的元素为谓词p
回报false。元素的相对顺序被保存. 原文:
Reorders the elements in the range
[first, last)
in such a way that all elements for which the predicate p
returns true precede the elements for which predicate p
returns false. Relative order of the elements is preserved. 目录 |
[编辑] 参数
first, last | - | 范围内的元素进行重新排序
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p | - | unary predicate which returns true 如果该元素的,要责令之前的其他元素 . 原文: if the element should be ordered before other elements The signature of the predicate function should be equivalent to the following: bool pred(const Type &a); The signature does not need to have const &, but the function must not modify the objects passed to it. |
类型要求 | ||
-BidirIt 必须满足 ValueSwappable 和 BidirectionalIterator 的要求。
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-The type of dereferenced BidirIt must meet the requirements of MoveAssignable and MoveConstructible .
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[编辑] 返回值
迭代器到第二组的第一个元素
原文:
Iterator to the first element of the second group
[编辑] 复杂度
究竟
last-first
应用程序的谓词和最(last-first)*log(last-first)
掉期,如果有足够的内存或线性的掉期,如果有足够的可用内存.原文:
Exactly
last-first
applications of the predicate and at most (last-first)*log(last-first)
swaps if there is insufficient memory or linear number of swaps if sufficient memory is available.[编辑] 示例
#include <iostream> #include <algorithm> int main() { std::vector<int> v{0, 0, 3, 0, 2, 4, 5, 0, 7}; std::stable_partition(v.begin(), v.end(), [](int n){return n>0;}); for (int n : v) { std::cout << n << ' '; } std::cout << '\n'; }
输出:
3 2 4 5 7 0 0 0 0
[编辑] 另请参阅
把一个区间的元素分为两组 (函数模板) |