std::is_sorted
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在头文件 <algorithm> 中定义
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template< class ForwardIt > bool is_sorted( ForwardIt first, ForwardIt last ); |
(1) | (C++11 起) |
template< class ForwardIt, class Compare > bool is_sorted( ForwardIt first, ForwardIt last, Compare comp ); |
(2) | (C++11 起) |
Checks if the elements in range [first, last)
are sorted in ascending order. The first version of the function uses operator< to compare the elements, the second uses the given comparison function comp
.
目录 |
[编辑] 参数
first, last | - | 检查的元素
|
comp | - | comparison function which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following: bool cmp(const Type1 &a, const Type2 &b); The signature does not need to have const &, but the function must not modify the objects passed to it. |
类型要求 | ||
-ForwardIt 必须满足 ForwardIterator 的要求。
|
[编辑] 返回值
true if the elements in the range are sorted in ascending order
[编辑] 复杂度
线性
first
和last
之间的距离原文:
linear in the distance between
first
and last
[编辑] 可能的实现
版本一 |
---|
template<class ForwardIt> bool is_sorted(ForwardIt first, ForwardIt last) { return std::is_sorted_until(first, last) == last; } |
版本二 |
template<class ForwardIt, class Compare> bool is_sorted(ForwardIt first, ForwardIt last, Compare comp) { return std::is_sorted_until(first, last, comp) == last; } |
[编辑] 示例
#include <iostream> #include <algorithm> int main() { const int N = 5; int digits[N] = {3, 1, 4, 1, 5}; for (auto i : digits) std::cout << i << ' '; std::cout << ": is_sorted: " << std::is_sorted(digits, digits+N) << '\n'; std::sort(digits, digits+N); for (auto i : digits) std::cout << i << ' '; std::cout << ": is_sorted: " << std::is_sorted(digits, digits+N) << '\n'; }
输出:
3 1 4 1 5 : is_sorted: 0 1 1 3 4 5 : is_sorted: 1
[编辑] 另请参阅
(C++11) |
查找最大有序子区间 (函数模板) |