std::basic_string::rfind
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< cpp | string | basic string
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size_type rfind( const basic_string& str, size_type pos = npos ) const; |
(1) | |
size_type rfind( const CharT* s, size_type pos, size_type count ) const; |
(2) | |
size_type rfind( const CharT* s, size_type pos = npos ) const; |
(3) | |
size_type rfind( CharT ch, size_type pos = npos ) const; |
(4) | |
Finds the last substring equal to the given character sequence. Search begins at pos
, i.e. only the substring [0, pos)
is considered in the search. If npos
is passed as pos
whole string will be searched.
1) Finds the last substring equal to str
.
2) Finds the last substring equal to the first count
characters of the character string pointed to by s
. s
can include null characters.
3) Finds the last substring equal to the character string pointed to by s
. The length of the string is determined by the first null character.
4) Finds the last character ch
.
目录 |
[编辑] 参数
str | - | 要搜索的字符串
|
count | - | 要搜索的子字符串的长度
|
s | - | 指针一个字符串SEACH
原文: pointer to a character string to seach for |
ch | - | 搜索字符
|
[编辑] 返回值
找到的字符串或
npos
的第一个字符的位置,如果没有这样的子被找到原文:
position of the first character of the found substring or
npos
if no such substring is found.[编辑] 示例
#include <string> #include <iostream> void print(std::string::size_type n, std::string const &s) { if(n == std::string::npos) std::cout << "not found\n"; else std::cout << "found: " << s.substr(n) << '\n'; } int main() { std::string::size_type n; std::string const s = "This is a string"; // search backwards from beginning of string n = s.rfind("is"); print(n, s); // search backwards from position 4 n = s.rfind("is", 4); print(n, s); // find a single character n = s.rfind('s'); print(n, s); // find a single character n = s.rfind('q'); print(n, s); }
输出:
found: is a string found: is is a string found: string not found
[编辑] 另请参阅
找到字符串中的字符 (公共成员函数) | |
第一次出现的字符 (公共成员函数) | |
找到第一个没有的字符 (公共成员函数) | |
最后一次出现的字符 (公共成员函数) | |
找到最后没有的字符 (公共成员函数) |