std::chrono::time_point::max
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< cpp | chrono | time point
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static constexpr time_point max(); |
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返回一个
time_point
与可能的最大持续时间,即std::chrono::time_point(std::chrono::duration::max()).原文:
Returns a
time_point
with the largest possible duration, i.e. std::chrono::time_point(std::chrono::duration::max()).[编辑] 参数
(无)
[编辑] 返回值
的最大可能的
time_point
[编辑] 示例
#include <chrono> #include <vector> #include <iostream> int main() { std::chrono::time_point<std::chrono::system_clock> now = std::chrono::system_clock::now(); std::vector<std::chrono::time_point<std::chrono::system_clock>> times { now - std::chrono::hours(24), now - std::chrono::hours(48), now + std::chrono::hours(24), }; std::chrono::time_point<std::chrono::system_clock> earliest = std::chrono::time_point<std::chrono::system_clock>::max(); std::cout << "all times:\n"; for (const auto &time : times) { std::time_t t = std::chrono::system_clock::to_time_t(time); std::cout << std::ctime(&t); if (time < earliest) earliest = time; } std::time_t t = std::chrono::system_clock::to_time_t(earliest); std::cout << "earliest:\n" << std::ctime(&t); }
Possible output:
all times: Sun Oct 7 19:06:48 2012 Sat Oct 6 19:06:48 2012 Tue Oct 9 19:06:48 2012 earliest: Sat Oct 6 19:06:48 2012